NCUSO4 = 0,02 MOL + TH I GIAN T1 = 200S S MOL E TRAO Đ I IT 9, 65*...

Câu 3: nCuSO

₄

= 0,02 mol

+ Th i gian t

1

= 200s

S mol e trao đ i

It 9, 65* 200

  

n 0, 02(mol)

F 96500



 

2

Cu 2e Cu

 

0, 01 0, 02 0, 01

 

m 0, 01*64 0, 64(gam)

Cu

+ Th i gian t

2

= 500s

It 9, 65*500

n 0, 05(mol)

0, 02 0, 04 0, 02

m 0, 02*64 1, 28(gam)

áp án : C