80% = 4000 GAMC H O 0 C H OH COLªN MEN6 12 6 2 2 5 2 232 C180 GAM 92 GAM4000 GAM X GAM

2. m = 5000 . 80% = 4000 gamC H O 

0

C H OHCO

lªn men

6

12

6

2

2

5

2

2

32 C

180 gam 92 gam4000 gam x gam