180 2     6 12 6C H O A GAM A A H O H6 12 6 , A A

Câu 38: C H O a mol: :180 2     

6

12

6

C H O a gam a a





H O H

6

12

6

,

 a a.2 .4 0, 6

2

 C H O a gam2: 2 180 342

12

22

11

:342C H O mol   3a 52,169( )m m m gam

C H O

C H O

6

12

6

12

22 11

áp án: A