A) P = 2 A A 1 7 A 3 A 3 A 3 ( A 3)( A 3)   32(3)(1)(3)7276433A...

Câu 2: a) P = ^{2 a a 1 7 a 3}

 

a 3 a 3 ( a 3)( a 3)

   

3

2

(

)

1

)(

7

6

4

a





 

= ( 3 )( 3 )

9

= 3

 

Vậy P = ^{3 a}

a 3  .

b) P < 1  3 a 1 3 a a 3 a 3 0 a 9

2 4

a 3         

 .