(AB+CD) 2 (A 2 +C 2 )( B 2 +D 2 ) <=> A 2 B 2 +2ABCD+C 2 D 2 A 2 B 2 + A 2 D 2 +C 2 B 2 +C 2 D 2 <=> 0 A 2 D 2 - 2CBCD+C 2 B 2 <=> 0 (AD - BC) 2 (ĐPCM ) DẤU = XÃY RA KHI AD=BC

1) Ta có : (ab+cd) 2 (a 2 +c 2 )( b 2 +d 2 ) <=>

a 2 b 2 +2abcd+c 2 d 2 a 2 b 2 + a 2 d 2 +c 2 b 2 +c 2 d 2 <=>

0 a 2 d 2 - 2cbcd+c 2 b 2 <=>

0 (ad - bc) 2 (đpcm )

Dấu = xãy ra khi ad=bc.