2. ABCDEFGH is an octagon in which all eight angles are equal.
If AB = 7, BC = 4, CD = 2, DE = 5, EF = 6 and FG = 2, determine the sum of
the lengths of GH and HA .
F E
G
D
C
H
【Solution】
A B
Extend AB , CD , EF and GH to form a quadrilateral
R Q
PQRS . Each angle of ABCDEFGH is 135 ◦ . Hence
2 6
5
each of PCB , QED , RGF and SAH are 45 ◦ −45 ◦ −90 ◦
triangles. It follows that PQRS is a rectangle. We have
2
= 2
2 =2 2 , QE = QD = 5 5 2
PB = PC = 4
4
2 and
7
S
A B P
RG = RF = 2
2 = 2 .
Hence
5 2 3 2
SH = SA = SP − AB − BP = RQ − AB − BP = + + − − = − so
( 2 6 7 2 2) 1
2 2
that HA=3 − 2 . Also,
(2 2 2 ) 2 ( 1) 3 2 2
GH = RS − RG − SH = QP − RG − SH = + + − − − = +
It follows that GH + HA = + 6 2
Ans: 6 + 2
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