BÀI 2 VT= (O⃗A+OC⃗)+(O⃗B+O⃗D)=⃗O+⃗O=⃗O 5( 3 ĐIỂM )B, CMR

Question

1,0⇔O⃗M+M⃗A+O⃗M+M⃗B+O⃗M+M⃗C+O⃗M+M⃗D=O0,5⇔M⃗A+M⃗B+M⃗C+M⃗D=4M⃗O⇒dfcma, do  M⃗A −2M⃗B=⃗O⇔M⃗A=2M⃗B

Answer

1,0⇔O⃗M+M⃗A+O⃗M+M⃗B+O⃗M+M⃗C+O⃗M+M⃗D=O0,5⇔M⃗A+M⃗B+M⃗C+M⃗D=4M⃗O⇒dfcma, do  M⃗A −2M⃗B=⃗O⇔M⃗A=2M⃗B