0.5Đ NT = N0 (1+ %B -%D+%I-%E)T N2 = 11000 (1 + 0.12 - 0.08 + 0.01 - 0...
Câu 3: 0.5đ
N
t
= N
0
(1+ %B -%D+%I-%E)
t
N
2
= 11000 (1 + 0.12 - 0.08 + 0.01 - 0,02)
2
= 11670
Câu 3: 0.5đ
N
t
= N
0
(1+ %B -%D+%I-%E)
t
N
2
= 11000 (1 + 0.12 - 0.08 + 0.01 - 0,02)
2
= 11670