FAN OF TYPE 0, WHERE NJ = 2(AJ +A2J + 1) AND MJ = A2J(AJ + 1)2. BY T...
2-fan of type 0, where n
j
= 2(aj
+a2
j
+ 1) and mj
= a2
j
(aj
+ 1)2
. By the way, also cj
isinvolved, namely kj
0
= (cj
−1)2
/2, where k0
j
(nj
−k0
j
) =mj
. aProposition2.3. G×
+
contains infinitely many 2-fans of type 1.Proof. By Theorem 2.1, n, n−1, n−2, m is a 2-fan of type 1 if and only if n = 2a2
+ 1,8a2
+ 1 is an integer. Now, 8a2
+ 1 is odd, and thus, if 8a2
+ 1m = a2
(a2
−1) and √is a square, then there is a t such that 8a2
+ 1 = (2t+ 1)2
. Consequently we get 8a2
=4t2
+ 4t= 4t(t+ 1), which impliesa2
= t(t+ 1)