6.9 t
pdr = 0.0400 + 4.5253*0.0039h (in units of ns) = 3.22 + 1.42h (in units of τ)
t
pdf = 0.0242 + 2.8470*0.0039h (in units of ns) = 1.95 + 0.90h (in units of τ)
g
u = 1.42; p
u = 3.22; g
d = 0.90; p
d = 1.95
As compared to input A, input B has a greater parasitic delay and slightly smaller
logical effort. Input B must be the outer input, which must discharge the parasitic
capacitance of the internal node, increasing its parasitic delay.
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