5. Draw BC–––tor has area 12π. ΔRNTconsistslength of the radius r. Then you can use theof two 30°-60°-90°triangles, withTPythagorean theorem to ﬁnd r:sides as marked, so its area is 82+r2=(r+6)2( ) ( ) ( )=. Therefore, half of the origi-1 2 6 3 3/ 9 3FOIL: 64 +r2=r2+12r+3612π −9 3nal shaded region is , and the whole isSubtract r2: 64 =12r+3624π −18 3.Subtract 36: 28 =12rDivide by 12: 7/3 =rThe circumference is 2πr,which is 2π(7/3) =14π/3.SAT Practice 862+x2=102Simplify: 36 +x2=100ABA A BSubtract 36: x2=64Take the square root: x=8

DRAW BC–––TOR HAS AREA 12Π. ΔRNTCONSISTSLENGTH OF THE RADIUS R. THE...

SAT MC GRAWHILL PART 42 PDF

5. Draw BC–––tor has area 12π. ΔRNTconsistslength of the radius r. Then you can use theof two 30°-60°-90°triangles, with

Pythagorean theorem to ﬁnd r:sides as marked, so its area is 8

=(r+6)

⁼. Therefore, half of the origi-1 2 6 3 3/ 9 3FOIL: 64 +r

+12r+3612π −9 3nal shaded region is , and the whole isSubtract r

: 64 =12r+3624π −18 3.Subtract 36: 28 =12rDivide by 12: 7/3 =rThe circumference is 2πr,which is 2π(7/3) =14π/3.SAT Practice 86

=10

Simplify: 36 +x

=100ABA A BSubtract 36: x

=64Take the square root: x=8