1 2 A         A 1 A 1 A (A 1) (A 1)          = ( A 1)2

Question

Câu 2: a) A = a 1 2 a : 1 2 a         a 1 a 1 a (a 1) (a 1)          = ( a 1)2 : 1 2 a ( a 1)2 : ( a 1)2a 1 a 1 (a 1)( a 1) a 1 ( a 1)(a 1)         .  = ( a 1) (a 1)( a 1)2. 2 a 1 a 1 ( a 1)  .b) a = 2011 - 2 2010  ( 2010  1 )2  a  2010  1Vậy A = 2010 .1 ta có:

Answer

Câu 2: a) A = a 1 2 a : 1 2 a         a 1 a 1 a (a 1) (a 1)          = ( a 1)2 : 1 2 a ( a 1)2 : ( a 1)2a 1 a 1 (a 1)( a 1) a 1 ( a 1)(a 1)         .  = ( a 1) (a 1)( a 1)2. 2 a 1 a 1 ( a 1)  .b) a = 2011 - 2 2010  ( 2010  1 )2  a  2010  1Vậy A = 2010 .1 ta có:

1 2 A         A 1 A 1 A (A 1) (A 1)          = ( A 1)2

Câu 2: a) A = ^{a 1 2 a} : ¹ ^{2 a}

   

      

a 1 a 1 a (a 1) (a 1)

   

 

      

= ^{( a 1)}

: ¹ ^{2 a} ^{( a 1)}

: ^{( a 1)}

a 1 a 1 (a 1)( a 1) a 1 ( a 1)(a 1)

         .

  

= ( a 1) (a 1)( a 1)

.

a 1

 

a 1 ( a 1)

  .

b) a = 2011 - 2 2010  ( 2010  1 )

 a  2010  1

Vậy A = 2010 .

1 ta có:

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