MATHEMATICS2= 2.5. 114= 1.25. 2.5 × 1.25 = 3.125 OR 3 8

29. a. The amount of water held in each container

sum of ages of 110 years. Therefore, J + G = 110.

Jerry was one-third as young as his grandfather 15

must be found. The rectangular box starts with 16

square inches times 9 inches = 144 cubic inches of

years ago. Therefore, J – 15 =

(G – 15). Solve the

water. The cylindrical container can hold

first equation for J: J = 110 – G. Now substitute