/ X(X + 5) – 3(X + 5) = 0 B/ X2– 6X – 7 = 0 C/ (2 X  3)2  (3 X  2)2

Bài 2(1.5đ): Tìm x, biết:

/ x(x + 5) – 3(x + 5) = 0 b/ x

2

– 6x – 7 = 0 c/ (2 x 3)

2

(3 x 2)

2