NH2N-CH2-CH2-CH2- CH2- COOH  → (-HN-(CH2)4 - CO-)N + NH2OB

4/ - DE THI HSG HAI PHONG
Lớp 12 DE THI HSG HAI PHONG
4/ ( 1,0 điểm)A: nH

2

N-CH

2

-CH

2

-CH

2

- CH

2

- COOH

 →

(-HN-(CH

2

)

4

- CO-)

n

+ nH

2

OB: CH

3

-CH

2

-CH(NH

2

)- CH

2

- COOH

 →

CH

3

-CH

2

-CH=CH- COOH + NH

3

C: CH

3

-CH(NH

2

)-CH

2

- CH

2

- COOH

 →

+ H

2

OH

3

C