FOR SOME VALUE OFX, 5(X+ 2) = Y. AFTER THE VALUEFORMULAS

17. For some value ofx, 5(x+ 2) = y. After the valueformulas:ofxis increased by 3, 5(x+ 2) = z. What is the

[

aa

3

1

aa

4

2

]

[

bb

3

1

bb

2

4

]

[

aa

3

1

bb

1

1

+ a+ a

4

2

bb

3

3

aa

3

1

bb

2

2

+ a+ a

4

2

bb

4

4

]

× =value ofz– y?