EXERCISE 6WORK OUT EACH PROBLEM. FOR QUESTIONS 1–4, CIRCLE THE LETTER...

3. (C) Since the hexagon is regular (all sides areline’s slope

^m

⁼

_x

^y

¹

⁻

₋

^y

_x

²

. Accordingly,congruent), the area of ∆AOP in the following

1

2

5

3

(

)

1

figure is

3

— one sixth the area of the

−

a

. Simplify, then cross-multiply to

=

− −

2

3

hexagon.solve for a:

8

=

−

2

a

−

=

2

3 8

( )( )

2

24

=

26