68 = 74,5(A + E) + 111(B + C + D) + 32(32 2SO2O2 XT T,O2SO3A B C 3A6B2CMOL 3 3
83,68 = 74,5(a + e) + 111(b + c + d) + 32(
3
2
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O
2
xt t
,
o
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a
b c
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a
6
b
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Mol
3
3
83,68 = 74,5(a + e) + 111(b + c + d) + 32(
3
2
2
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2
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2
xt t
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3
a
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Mol
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3