4Z1=4−3I+1−3I+3I2−I3=2−5I4Z2=2+4I−2(1−3I+3I2−I3)1+I =(6+8I)(1−I)...
2015)
4
z
1
=
4−3
i+
1−3
i+
3
i
2
−i
3
=2−5
i
4
z
2
=
2+
4
i−2(1−3
i+
3
i
2
−i
3
)
1+
i
=
(6
+
8
i)(1−i
)
1
2
+
1
2
=7+
i
(0,25 đ)
Suy ra
z
1
z
2
=(
2+5
i
)(7+
i)=9+
37
i=¿
w=2
(9−37
i
)=18−74
i
(0,25 đ)
Vậy Rew = 18; lmz = -74
(0,25 đ)