4Z1=4−3I+1−3I+3I2−I3=2−5I4Z2=2+4I−2(1−3I+3I2−I3)1+I =(6+8I)(1−I)...

2015)

4

z

1

=

4−3

i+

1−3

i+

3

i

2

−i

3

=2−5

i

4

z

2

=

2+

4

i−2(1−3

i+

3

i

2

−i

3

)

1+

i

=

(6

+

8

i)(1−i

)

1

2

+

1

2

=7+

i

(0,25 đ)

Suy ra

z

1

z

2

=(

2+5

i

)(7+

i)=9+

37

i=¿

w=2

(9−37

i

)=18−74

i

(0,25 đ)

Vậy Rew = 18; lmz = -74

(0,25 đ)