2 + J J / 2J + 2 / 2J (J + 2) / 2J IF THE TWO OF THEM FINISH THE R...

1/2 + 1/J

J / 2J + 2 / 2J

(J + 2) / 2J

If the two of them finish the room in one hour, using the formula of

rt = w, we can solve for J.

rt = w and t = 1 (hour), w = 1 (job)

((J + 2) / 2J )(1) = 1

J + 2 = 2J

J = 2

That means that Joseph’s rate is 1/2, the same as Lindsay’s. The

question though asks us what fraction of the room Joseph would

complete in 20 minutes, or 1/3 of an hour.

rt = w

(1/2)(1/3) = w

w = 1/6

Now we must look at the answer choices to see which one is equal

to 1/6 when we plug in x = 6. Only C works: (6 – 3) / 18 = 1/6.

The correct answer is C.