2 + J J / 2J + 2 / 2J (J + 2) / 2J IF THE TWO OF THEM FINISH THE R...
1/2 + 1/J
J / 2J + 2 / 2J
(J + 2) / 2J
If the two of them finish the room in one hour, using the formula of
rt = w, we can solve for J.
rt = w and t = 1 (hour), w = 1 (job)
((J + 2) / 2J )(1) = 1
J + 2 = 2J
J = 2
That means that Joseph’s rate is 1/2, the same as Lindsay’s. The
question though asks us what fraction of the room Joseph would
complete in 20 minutes, or 1/3 of an hour.
rt = w
(1/2)(1/3) = w
w = 1/6
Now we must look at the answer choices to see which one is equal
to 1/6 when we plug in x = 6. Only C works: (6 – 3) / 18 = 1/6.
The correct answer is C.