M AMINO AXIT = 147 => HOOC-[CH 2 ] 2 -CH(NH 2 )-COOH HOOC-[CH 2 ]...

Câu 45:

M amino axit = 147 => HOOC-[CH 2 ] 2 -CH(NH 2 )-COOH

HOOC-[CH 2 ] 2 -CH(NH 2 )-COOH + HCl  → HOOC-[CH 2 ] 2 -CH(NH 3 Cl)-COOH

HOOC-[CH 2 ] 2 -CH(NH 2 )-COOH + 2NaOH  → NaOOC-[CH 2 ] 2 -CH(NH 2 )-COONa + 2H 2 O

Đáp án: C