+       X - 1X - 1 X - X X + 1     = X - 1X - X ( X - 1)1

Câu 1: a) M = x 1 1 2 - : +       x - 1x - 1 x - x x + 1     = x - 1x - x ( x - 1)1 :

x - 1

 

x - 1x + 1

 

+ x - 1

 

2 x +1

       : = . = x - 1

  

x + 1

   

x - 1

 

x - 1

 

x + 1

x + 1x x - 1 x - 1 x +1 x x - 1= x - 1x .b) M > 0  x - 1 > 0 (vì x > 0 nên x > 0)  x > 1. (thoả mãn)