(3Đ) F(X) =X17 – 1999X16 – X16 + 1999X15 + X15 – 1999X14 - X14+…+1999X + X – 1 F(1999) = 199917 - 199917 - 199916 + 199916 + 199915 - 199915- 199914+…+19992+1999 – 1 = 1999 – 1 = 1998

1. (3đ)

f(x) =x

17

– 1999x

16

– x

16

+ 1999x

15

+ x

15

– 1999x

14

- x

14

+…+1999x + x – 1

f(1999) = 1999

17

- 1999

17

- 1999

16

+ 1999

16

+ 1999

15

- 1999

15

-

1999

14

+…+1999

2

+1999 – 1

= 1999 – 1 = 1998.