(3Đ) F(X) =X17 – 1999X16 – X16 + 1999X15 + X15 – 1999X14 - X14+…+1999X + X – 1 F(1999) = 199917 - 199917 - 199916 + 199916 + 199915 - 199915- 199914+…+19992+1999 – 1 = 1999 – 1 = 1998
1. (3đ)
f(x) =x
17
– 1999x
16
– x
16
+ 1999x
15
+ x
15
– 1999x
14
- x
14
+…+1999x + x – 1
f(1999) = 1999
17
- 1999
17
- 1999
16
+ 1999
16
+ 1999
15
- 1999
15
-
1999
14
+…+1999
2