NAOHO2CH − CH CL → CH − CH − OH → CH COOH3 2 3 2 MEN 3CH − CH+O MN3 32 2DDKMNO H SO= → − → −4 2 4CH CH CH OH CH OH CH CHO2 2 2 2 3
Câu 6. Đáp án : B.
NaOH
O
2
CH − CH Cl → CH − CH − OH → CH COOH
3
2
3
2
men
3
CH − CH
+
O Mn
3
3
2
2
ddKMnO
H SO
= → − → −
4
2
4
CH CH CH OH CH OH CH CHO
2
2
2
2
3
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