24KHI IC=0  UCE = E = 12VKHI UCE = 0  IC = E/(R3+R4) = 24MAP IB=...

3, - DAP AN DIEN TU TUONG TU
DAP AN DIEN TU TUONG TU

3,24

Khi I

c

=0  U

CE

= E = 12V

Khi U

CE

= 0  I

C

= E/(R

3

+R

4

) = 3,24mA

P I

B

=15A