CÂU 53 GI S S MOL KCL SINH RA M I THÍ NGHI M Đ U B NG 1 (MOL) -...

3/5 <--- 1

heo PT (2): nCl2(TN2) = 3/5nKCl = 3/5 (mol)

Ta có: nCl2(TN1)/nCl2(TN2) = 1/3/5 = 5/3