(1Đ) C = 3600 – (650+ 1170+ 700) = 3600 - 2520 = 1080 (1Đ)

Câu 7 (1đ)

C

= 360

0

– (65

0

+ 117

0

+ 70

0

)

= 360

0

- 252

0

= 108

0

(1đ)