A) MG + 2HCL → MGCL2 + 2 (1)MGO + 2HCL → MGCL2 + H2O (2)B) THEO PTHH (...
Câu 2 :a) Mg + 2HCl → MgCl
2
+2
(1)MgO + 2HCl → MgCl2
+ H2
O (2)b) Theo PTHH (1) có nMg
= nkhí
= 0,05 mol→ mMg
= 0,05.24 = 1,2 gam; mMgO
= 9,2 – 1,2 = 8 gam.