AH ONAOH1500 CO → CH4→ CH3CHO → → CH ≡ CH 22CH3COONA OHG +CAO, TP, TO= →CH CHO→ CH3COOH →CH CH≡222 XT| OCOCHMN +3→ ( − CH2 − CH − )NOCOCH3 |
Câu 215. Đáp án : A
H O
NaOH
1500 C
o
→ CH
4
→ CH
3
CHO →
→ CH ≡ CH
2
2
CH
3
COONa
o
Hg
+
CaO, t
p, t
o
= →
CH CH
O
→ CH
3
COOH →
CH CH
≡
2
2
2
xt
| OCOCH
Mn
+
3→ ( − CH
2
− CH − )
n
OCOCH3 |
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