B RCOOH + KOH RCOOK + H2O RCOOH + NAOH RCOONA + H2O NNAOH = NKOH...
Bài 5: B
RCOOH + KOH RCOOK + H
2
O
RCOOH + NaOH RCOONa + H
2
O
n
NaOH
= n
KOH
= 0,5.0,12 = 0,06 mol
ĐLBTKL: m
X
+ m
NaOH
+ m
KOH
= m
rắn
+
m
H
2
O
m = 1,08 gam n = 0,06 mol
H
2
O
H
2
O
60
,
3 = 60 R = 15
n
RCOOH
= n = 0,06 mol M
X
= R + 45 =
H
2
O
0
06
X: CH
3