TỔNG C20170 C12017C20172 ...C10082017 BẰNG

Câu 41: Tổng C

2017

0

C

1

2017

C

2017

2

...C

1008

2017

bằng: A. 2

1008

B. C

1010

2017

C

1011

2017

C

1012

2017

...C

2017

2017

.C. 2

2017

. D. C

1009

2017

C

1010

2017

C

1011

2017

...C

2017

2017

.

2

2 3 x x