M N P0P0N= VM P0N Q0
4.V
P.M N P0
P
0N
= V
M P0
N Q0
.P N0
Q− 4. 1
2 V
P.M Q0
N P0
= V
M P0
N Q0
.M0
P N0
Q− 2V
P.M Q0
N P0
= V
M P0
N Q0
.P N0
Q− 2. 1
3 V
M P0
N Q0
.P N0
Q= 1
M
03 V
M P0
N Q0
.P N0
Q.
Q
⇒ 1
3 V
M P0
N Q0
.P N0
Q= 36(dm
3) ⇔ V
M P0
N Q0
.P N0
Q= 108 (dm
3)
Do M N ⊥P Q, P Q//P
0Q
0nên M N ⊥P
0Q
0⇒ M P
0N Q
0là hình
vuông
P N
0
√ 2 = 30 √
M Q = 60
2(cm) = 3 √
2(dm)
Ta có: M N = 60cm ⇒
OM = 60
2 = 30(cm) = 3(dm)
⇒ S
M P0
N Q0
= 3 √
2
2= 18(dm
2)
V
M P0
N Q0
.P N0
Q= S
M P0
N Q0