1) Xét hàm số: f x ( ) (1 x ) n 1 (1 x C ) n 0 xC n 1 x C 2 n 2 x C 3 n 3 ... x C n n n
(1 x C ) n 0 ( x x C 2 ) 1 n ( x 2 x C 3 ) n 2 ( x 3 x C 4 ) n 3 ... ( x n x n 1 ) C n n
Ta có: f x ( ) (1 x ) n 1 f x '( ) ( n 1)(1 x ) n f "( ) x ( n 1) (1 n x ) n 1 f "(1) ( n 1) .2 n n 1
hay f x ( ) (1 x C ) n 0 ( x x C 2 ) 1 n ( x 2 x C 3 ) n 2 ( x 3 x C 4 ) n 3 ... ( x n x n 1 ) C n n
0 1 2 2 2 3 3 1
n n n
'( ) (1 2 ) (2 3 ) (3 4 ) ... ( ( 1) )
f x C x C x x C x x C nx n x C
n n n n n
1 2 2 3 2 1
"( ) 2 (2 6 ) (6 12 ) ... ( ( 1) ( 1) )
f x C x C x x C n n x n nx C
n n n n
n
1 2 2 2 3 2
f C C C n C
"(1) 2 2.2 2.3 ... 2
1 2 2 2 3 2 1 1 2 2 2 3 2 2
2 C n 2.2 C n 2.3 C n ... 2 n C n n ( n 1) .2 n n C n 2 C n 3 C n ... n C n n ( n 1) .2 n n
Khi n 2012 , ta có: 1 2 C 2012 1 2 2 C 2012 2 3 2 C 2012 3 ... 2012 2 C 2012 2012 2013.2012.2 2010 =S
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