F X ( )  (1  X ) N  1  (1  X C )  N 0  XC N 1  X C 2 N 2  X C 3 N 3 

1) Xét hàm số: f x ( )(1x ) n 1(1x C )n 0xC n 1x C 2 n 2x C 3 n 3...x C n n n

 (1  x C ) n 0  ( xx C 2 ) 1 n  ( x 2x C 3 ) n 2  ( x 3x C 4 ) n 3  ... (  x nx n 1 ) C n n

Ta có: f x ( )  (1  x ) n 1f x '( )  ( n  1)(1  x ) nf "( ) x  ( n  1) (1 nx ) n 1f "(1)  ( n  1) .2 n n 1

hay f x ( )  (1  x C ) n 0  ( xx C 2 ) 1 n  ( x 2x C 3 ) n 2  ( x 3x C 4 ) n 3  ... (  x nx n 1 ) C n n

0 1 2 2 2 3 3 1

n n n

'( ) (1 2 ) (2 3 ) (3 4 ) ... ( ( 1) )

f x C x C x x C x x C nx n x C

           

n n n n n

1 2 2 3 2 1

 

          

"( ) 2 (2 6 ) (6 12 ) ... ( ( 1) ( 1) )

f x C x C x x C n n x n nx C

n n n n

n

1 2 2 2 3 2

     

f C C C n C

"(1) 2 2.2 2.3 ... 2

1 2 2 2 3 2 1 1 2 2 2 3 2 2

2 C n 2.2 C n 2.3 C n ... 2 n C n n ( n 1) .2 n n C n 2 C n 3 C n ... n C n n ( n 1) .2 n n

             

Khi n  2012 , ta có: 1 2 C 2012 1  2 2 C 2012 2  3 2 C 2012 3  ... 2012  2 C 2012 2012  2013.2012.2 2010 =S