(X + (X + 2) = 0  X + 1 = 0 HAY X + 2 = 0  X = -1 HAY X = -25Y 15 (( 2(2))Y 32 1 (X Y     X 7 2YX 1X Y 2 7 (2)     

1) (x + 1)(x + 2) = 0  x + 1 = 0 hay x + 2 = 0  x = -1 hay x = -2

5y 15 ((1) 2(2))

y 3

2 1 (1)

x y

 

 

 

 

 

x 7 2y

x 1

x y

2 7 (2)

  

 