Π2ZHIF2(X) + 2 √2F (X) COS X + ΠDX = 2 − Π4200

Câu 49.

π

2

Z

h

i

f

²

(x) + 2 √

2f (x) cos

x + π

dx = 2 − π

4

2

0

18

i

2

⇒

f(x) + √

2 cos

dx

cos

²

2 + 2

Z

2

2x + π

= 2 − π

1 + cos

2 +

x + 1

2 cos 2x

= 0

⇒ f (x) = − √

cos

f (x) dx = − √

= −1 + 1 = 0.

dx = − √

2 sin